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Re: using the "source" command in a "for" loop

X-seq: zsh-users 577
From: Timothy J Luoma <luomat@xxxxxxxx>
To: greg haygood <greg@xxxxxxxx>
Subject: Re: using the "source" command in a "for" loop
Date: Thu, 2 Jan 97 16:12:23 -0500
Cc: zsh-users@xxxxxxxxxxxxxxx
In-reply-to: <3.0.32.19970102160304.0098b380@xxxxxxxxxxxx>
Organization: Princeton Theological Seminary
References: <3.0.32.19970102160304.0098b380@xxxxxxxxxxxx>
Reply-to: luomat@xxxxxxxx

Responding To:	greg haygood <greg@xxxxxxxx>
Original Date:	Thu, 02 Jan 1997 16:03:05 -0500
Message-ID: 	<3.0.32.19970102160304.0098b380@xxxxxxxxxxxx>

> # need to export the vars, or they're lost when leaving the loop

Your fix worked.

I guess something changed because this even worked for 3.0.0.  No  
matter, as long as it works now

I changed:
	$i="$ZDOTDIR/$i"
to
	export $i="$ZDOTDIR/$i"

Thanks!

TjL

--
	Tj Luoma (luomat@xxxxxxxx)
		http://www.next.peak.org/~luomat
			Awaiting Apple's NeXTStep

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