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Re: is a key of pointed key set ? (where is the + )



Andrey Borzenkov wrote:
Somewhat kludgy but

yes it is :) but ...

I believe this was discussed recently. Parameter type is not propagated from nested substitutions, so this is not going to work. Outside of innermost ${...} you just get list of values. Even without (P):


misunderstood this point: i'll search into the archives.

regards



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