Re: lines to array

[Meino Christian Cramer <Meino.Cramer@xxxxxx>]

From: Peter Stephenson <pws@xxxxxxx>
Subject: Re: lines to array
Date: Wed, 14 Feb 2007 11:28:20 +0000

Hi,

 thanks a lot for the code and its explanation! :)

 One additional question: Is there a zshy way to sort
 the array and throw away any doubled entry ?

 Happy zshing!
 mcc



> "Christian Walther" <cptsalek@xxxxxxxxx> wrote:
> > On 14/02/07, Matt Wozniski <godlygeek@xxxxxxxxx> wrote:
> > > array=( "${(f)$(ls -l)}" )
> > 
> > Could you please explain what ${(f)...} actually does? Is there some
> > kind of parameter expansion going on?
> 
> Yes, the effect of (f) is described in "Parameter Expansion Flags" in the
> zshexpn manual page.  There's a hairy description below that of how nested
> parmaeter expansion works.  This counts as a nested parameter expansion
> even though the innermost level is actually a command substitution.
> 
> This gets explained every now and then on this list, but to recap:
> 
> $(...) inside parameter is treated as a normal command substitution.  The
> text for enclosing parameter expansion operations is the result of the
> command substitution rather than taken from a parameter.  Because of the
> double quotes, the command substitution produces a single word at this
> point.
> 
> (f) is documented as being equivalent to (ps:\n:).  The s:\n: forces the
> text to be split on \n. the p interprets the \n as a newline according to
> normal "print" rules.
> 
> The result is the text of "ls -l", split into lines.
> 
> You'll often see this written as
> 
> array=( ${(f)"$(ls -l)"} )
> 
> which indicates explicitly the only the command substitution is affected by
> the double quotes.  However, forced splitting (unlike automatic word
> splitting) overrides the double quotes anyway.
> 
> -- 
> Peter Stephenson <pws@xxxxxxx>                  Software Engineer
> CSR PLC, Churchill House, Cambridge Business Park, Cowley Road
> Cambridge, CB4 0WZ, UK                          Tel: +44 (0)1223 692070
> 
> 
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