Re: how to refer to basename of $0

[Tomasz Moskal <ramshackle.industries@xxxxxxxxx>]

On Thu, 2011-07-28 at 21:39 -0400, TJ Luoma wrote:
> Sorry folks, I'm explaining this really badly. Forget I said anything
> about bash. I don't care about bash. I'm trying to leave bash behind.
> 
> Let me start over. Here's what happens in zsh 4.3.11
> 
> # my comments are offset with #
> # fyi - "Air%" is my prompt
> 
> # just to show that $NAME is empty
> 	Air% echo $NAME
> 	Air%
> 
> 
> # /tmp/.source has only one line:
> 	Air% cat /tmp/.source
> 	NAME=`basename $0`
> 
> # here is my 'test.zsh' script:
> 	Air% cat ./test.zsh
> 	#!/bin/zsh
> 
> 	. /tmp/.source
> 
> 	echo "$NAME"
> 
>   	exit 0
> 
> # So now I run 'test.zsh' :
> 
> 	Air% ./test.zsh
> 	.source
> 
> # OK, so you can see that it output '.source' when I wanted it to
> output 'test.zsh'
> 
> # Next: rename /tmp/.source to ~/.zshenv
> 
> 	Air% mv /tmp/.source ~/.zshenv
> 
> # Edited 'test.zsh'  is now this:
> 
> 	Air% cat =test.zsh
> 	#!/bin/zsh
> 
> 	echo "$NAME"
> 
> 	exit 0
> 	#EOF
> 
> # now when I run 'test.zsh' again:
> 
> 	Air% test.zsh
> 	zsh
> 
> # Someone suggested "unsetopt function_argzero" so I added that to .zshenv:
> 
> 	Air% cat ~/.zshenv
> 	unsetopt function_argzero
> 
> 	NAME=`basename $0`
> 
> # and re-ran test.zsh, which gave me:
> 
> 	zsh
> 
> 
> Is it even possible to set NAME in .zsh* (and have it return
> 'test.zsh' or are they called too early in the process?
> 
> TjL

It's working here:

% cat .zshenv
unsetopt function_argzero
name=`basename $0`

% cat foo
#!/bin/zsh
. ~/.zshenv
echo $name
exit 0

% ./foo
foo

A bit perplexed, this is what I am... Have a look at this:

% zsh -f
% ./foo
foo