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Re: Mapping quoted parameter in function

On 10/11/16 13:29, Clint Hepner wrote:

On 2016 Nov 10 , at 1:20 a, Bernd Steinhauser <linux@xxxxxxxxxxxxxxxxxxxx> wrote:


I'm using a program that expects a parameter (actually multiple parameters) in the form
program "foo='bar'"

Because the cmdline for that program gets quite long, I wrote a function to call it and change parameters easily,it looks roughly like this:
progfunc() {
   program -n ${CORES} "foo='bar'" foo2="1 $3"

What I would want to do is to ensure that if I call
`progfunc x`

this would translate into "foo='x'", without touching the rest of the call.
Is that somehow possible?
iirc, variables won't work, because of the quoting style?

Best Regards,

Just replace bar with a parameter default expansion.

    progfunc () {
      program -n $CORES "foo='${1:-bar}' foo2="1 $3"

    progfunc              # foo='bar'
    progfunc "hi there"   # foo='hi there'

If you don’t pass a first argument, bar is used. Otherwise, the value of the argument is.

The single quotes here don’t actually quote anything; they are literal characters included in the *double*-quoted string.

Thanks, so my misunderstanding actually led me to not even try this.
Feels a bit embarrassing. ;)

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