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Re: capture stderr in command substitution

X-seq: zsh-users 26414
From: Ray Andrews <rayandrews@xxxxxxxxxxx>
To: zsh-users@xxxxxxx
Subject: Re: capture stderr in command substitution
Date: Mon, 25 Jan 2021 07:15:24 -0800
Archived-at: <https://zsh.org/users/26414>
Archived-at: <http://www.zsh.org/sympa/arcsearch_id/zsh-users/2021-01/38504cf6-a3c0-eb22-8a0b-6410d27ebbbc%40eastlink.ca>
In-reply-to: <20210124194750.dtyacd5emjauwxec@sym.noone.org>
List-id: <zsh-users.zsh.org>
References: <1eb9835c-3911-d4ea-6456-d9ad52ceffea@eastlink.ca> <20210124194750.dtyacd5emjauwxec@sym.noone.org>

On 2021-01-24 11:47 a.m., Axel Beckert wrote:


   $ var=$(command 2>&1)

Thanks, superficial testing shows it working fine. I finally sortaunderstand it too, you can read it as 'output #2 goes back to output #1.


var=$(cmd>&2)

That seems not to work but I'm in no mood to look into it so long as Axel's performs.

{ var=$(cmd 2>&1 >&3 3>&-); } 3>&1

... is not something that the eye's of a mortal should ever look upon ;-)

BTW (not worth starting a thread on this) how do you keep a command out of history?  I usta know this but can't remember and I've written it down somewhere but can't find it :(
I take a year off from coding anything and forget 101% of what I had learned.

Follow-Ups:
- Re: capture stderr in command substitution
  - From: Vin Shelton

References:
- capture stderr in command substitution
  - From: Ray Andrews
- Re: capture stderr in command substitution
  - From: Axel Beckert

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