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Re: (z) expansion flag do not always return an array

X-seq: zsh-users 27389
From: Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx>
To: Lawrence Velázquez <larryv@xxxxxxx>
Cc: Vincent Bernat <bernat@xxxxxxxx>, Zsh Users <zsh-users@xxxxxxx>
Subject: Re: (z) expansion flag do not always return an array
Date: Mon, 29 Nov 2021 09:45:23 -0800
Archived-at: <https://zsh.org/users/27389>
In-reply-to: <1be1289c-c3a1-4730-baab-5625af464cb1@www.fastmail.com>
List-id: <zsh-users.zsh.org>
References: <m3k0grdlls.fsf@luffy.cx> <1be1289c-c3a1-4730-baab-5625af464cb1@www.fastmail.com>

On Mon, Nov 29, 2021 at 8:51 AM Lawrence Velázquez <larryv@xxxxxxx> wrote:
>
> On Mon, Nov 29, 2021, at 10:31 AM, Vincent Bernat wrote:
> > The (z) expansion flag is documented to return an array
>
> Is it?  The 5.8 man page does not mention "array" even once.

True, but "split" usually implies $@ -variety results.  Also:

>         [...].  So to access single words in the result use nested
>         expansions as in `${${(z)foo}[2]}'.

That would lead one to believe that ${${(z)foo}[1]} also returns a
single word, but as PWS notes the context may alter that.

References:
- (z) expansion flag do not always return an array
  - From: Vincent Bernat
- Re: (z) expansion flag do not always return an array
  - From: Lawrence Velázquez

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