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Re: zsh-ify a bash script



On 1/20/22, Mikael Magnusson <mikachu@xxxxxxxxx> wrote:
> On 1/20/22, Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx> wrote:
>> On Wed, Jan 19, 2022 at 12:57 PM zzapper <zsh@xxxxxxxxxxxxxx> wrote:
>>>
>>> Dumb CLI trick. Wanted to find files containing all of several terms
>>> (dup2, pledge, socketpair, fork), but they could occur anywhere in the
>>> file:
>>
>> Not zsh any more than the first example, but instead of "grep -l" on
>> the entire file contents for each term ...
>>
>> # start by getting the actual occurrences of all the terms:
>> find . -name '*.c' | xargs egrep
>> '\<(dup2|pledge|fork|socketpair.*SOCK_STREAM)\>' /dev/null |
>> # reduce the results to just file names and search terms:
>> sed -E 's/(^[^:]*\.c:).*\<(dup2|pledge|fork|socketpair)\>.*/\1\2/' |
>> # make every search term unique per file:
>> sort -u |
>> # discard the search terms, leaving only file names:
>> cut -d : -f 1 |
>> # count the number of times each file name appears:
>> uniq -c |
>> # print names with a count of 4 (the number of search terms):
>> sed -nE 's/^ *4 //p'
>>
>> Adjusting this for edge cases where two search terms appear on the
>> same line is left as an exercise.
>
> This part would probably be fixed by passing -o to grep (didn't test
> in the above but):
> % echo foobar|grep -E '(foo|bar)'
> foobar
> % echo foobar|grep -oE '(foo|bar)'
> foo
> bar

I guess this is more or less the same solution,
% grep -Eo '(zsfree|zerr|subst)' Src/**/*.c|sort -u|sed
's/:[^:]*'//|uniq -c|grep -E '^\s+3'
      3 Src/Zle/zle_main.c
      3 Src/builtin.c
      3 Src/exec.c
      3 Src/glob.c
      3 Src/hist.c
      3 Src/jobs.c
      3 Src/signals.c
      3 Src/subst.c
      3 Src/utils.c


-- 
Mikael Magnusson




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