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"set -o foo" does not fail / does not abort the shell

I've tried the following with zsh-4.3.4-dev-4:

$ Src/zsh -f -c 'emulate sh; set -o foo; echo "Didn''t abort ($?)"'
set: no such option: foo
Didn't abort (0)

This is incorrect. The shell should abort as 'set' is a special

$ ksh93 -c 'set -o foo; echo "Didn''t abort ($?)"'
ksh93[1]: set: foo: bad option(s)
Usage: set [-sabefhkmnprtuvxBCGH] [-A name] [-o[option]] [arg ...]
zsh: exit 2     ksh93 -c 'set -o foo; echo "Didn't abort ($?)"'

[*] http://www.opengroup.org/onlinepubs/009695399/utilities/xcu_chap02.html#tag_02_08_01

See also the discussion on:

And in an interactive shell, "set -o foo" should return with a
non-zero exit status.

Please check the other special builtins:


Vincent Lefèvre <vincent@xxxxxxxxxx> - Web: <http://www.vinc17.org/>
100% accessible validated (X)HTML - Blog: <http://www.vinc17.org/blog/>
Work: CR INRIA - computer arithmetic / Arenaire project (LIP, ENS-Lyon)

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