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Re: Array as parameter



On 2 November 2011 13:06, Stephane Chazelas <stephane_chazelas@xxxxxxxx> wrote:
> 2011-11-02 11:14:38 +0100, Mikael Magnusson:
>> On 2 November 2011 10:10, Stephane CHAZELAS <stephane_chazelas@xxxxxxxx> wrote:
>> > 2011-11-1, 22:00(-07), Wayne Davison:
>> >> However, if you need to be able to keep the array
>> >> parameter separate from other parameters, you could instead refer to the
>> >> variable whose name you passed in using ${(P)1} in your function in place
>> >> of the $1.
>> >
>> > Except that it doesn't work for arrays. You'd need to  use eval
>> > here.
>>
>> (P) works perfectly fine with arrays.
> [...]
>
> Indeed, though it seems you have to write it as "${${(@P)1}[@]}", I'm not too sure why.

You need to specify @ at every nesting level that's inside double
quotes to prevent scalar joining. At the ${(P)b[@]} level, if that was
an implied question, the subscript is applied first:


> ~/install/cvs/pixz$ zsh -c 'a=("" "a b" c d); b=a; print -l "${${(P)b}[@]}"'
>  a b c d
> ~/install/cvs/pixz$ zsh -c 'a=("" "a b" c d); b=a; print -l "${${(@P)b}[@]}"'
>
> a b
> c
> d

But this is shorter,
% zsh -c 'a=("" "a b" c d); b=a; print -l "${(@P)b}"'

a b
c
d


-- 
Mikael Magnusson



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