Re: Possible bug with $~pattern, (#mi)

[Peter Stephenson <p.stephenson@xxxxxxxxxxx>]

On Wed, 7 Oct 2015 18:06:43 +0200
Sebastian Gniazdowski <sgniazdowski@xxxxxxxxx> wrote:
> When beg is used (this time correctly):
> 
> # a="1234"; beg="#"; echo ${a/$~beg(#mi)1/-}
> zsh: bad pattern: #(#mi)1

Bart's explained this in a more practical way, but you might want to
read the documentation.  It's not well written, actually: the point it's
making is that the # or % isn't part of the pattern, it's part of the
substitution syntax.  "The pattern may be preceded by..." or "The / may
be followed by..." would put it better, so I might change it.  "%" isn't
part of pattern syntax at all, so that would fail silently.

   The pattern may begin with a `#', in which case the pattern must
   match at the start of the string, or `%', in which case it  must
   match  at  the end of the string, or `#%' in which case the pat‐
   tern must match the entire string.  The repl  may  be  an  empty
   string,  in  which  case  the final `/' may also be omitted.  To
   quote the final `/' in other cases it should be  preceded  by  a
   single backslash; this is not necessary if the `/' occurs inside
   a substituted parameter.  Note also that the `#',  `%'  and  `#%
   are  not  active  if  they occur inside a substituted parameter,
   even at the start.

pws