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From: Bart Schaefer <schaefer@brasslantern.com>
Message-Id: <160118192908.ZM18534@torch.brasslantern.com>
Date: Mon, 18 Jan 2016 19:29:08 -0800
In-Reply-To: <160118163255.ZM3369@torch.brasslantern.com>
Comments: In reply to Bart Schaefer <schaefer@brasslantern.com>
        "Re: bufferwords() lexes a subshell in a shortloop repeat as a string" (Jan 18,  4:32pm)
References: <20160115062648.GA14019@tarsus.local2> 
	<20160115094117.5fcde75c@pwslap01u.europe.root.pri> 
	<160115112516.ZM21347@torch.brasslantern.com> 
	<20160117181647.49899357@ntlworld.com> 
	<160117144635.ZM3583@torch.brasslantern.com> 
	<20160118094129.260a60ae@pwslap01u.europe.root.pri> 
	<160118083658.ZM6465@torch.brasslantern.com> 
	<20160118165237.11b1349a@pwslap01u.europe.root.pri> 
	<160118163255.ZM3369@torch.brasslantern.com>
To: zsh-workers@zsh.org
Subject: Re: bufferwords() lexes a subshell in a shortloop repeat as a string
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On Jan 18,  4:32pm, Bart Schaefer wrote:
}
} Aside:  "emulate sh" does the equivalent of
} 
}     setopt shglob noglob nokshglob

My bad.  That's "ARGV0=sh zsh -f", not emulate.  I should not have
used -f there; mistaken history edit.

However, @(foo) is *parsed* as a pattern with only kshglob, but then
does NOT *match* as a pattern unless glob is also set.  

To get back on the original topic of this thread, here's more oddness
from bufferwords():

torch% print -l ${(z):-repeat 3 (echo foo;echo bar)}  
repeat
3
echo
foo
;
echo
bar
torch% 

Where did the parens go?  I suspect something is failing to set tokstr.
Without the (z) flag, the parens are interpreted as delimiting glob
qualifiers.