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Why zsh chose to be non-compliant in pattern matching

POSIX documentation for pattern matching (
http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_13_01)
said that any quoted characters in pattern will be match literally.

AFAICT, `["!"a]` will match `!` or `a`, most of shell behave like that
except zsh (and also ksh):

case a in ["!"a]) echo 1;; esac


print nothing. While:

case b in ["!"a]) echo 1;; esac


print 1. zsh treats `["!"a]` the same as `[!a]`.

Is there any reason for this behavior?

PS: The full question can be seen here
http://unix.stackexchange.com/q/265431/38906

Thanks.
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