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Re: print_exit_value unset in an scheduled function, yet still active



On Thu, 26 Sep 2019 at 21:49, Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx> wrote:
> If the question instead is "why did printexitvalue become unset inside
> the function":  It's always turned off on entry to a function, so that
> only the exit value of the function itself will later be printed,
> exactly as happened here.

Thanks, that was the question.

-- 
Sebastian Gniazdowski
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