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[Bug] $jobstates does not work in $()

X-seq: zsh-workers 49782
From: Carl Agrell <caagr98@xxxxxxxxx>
To: zsh-workers <zsh-workers@xxxxxxx>
Subject: [Bug] $jobstates does not work in $()
Date: Tue, 1 Mar 2022 01:46:05 +0100
Archived-at: <https://zsh.org/workers/49782>
List-id: <zsh-workers.zsh.org>

It appears that zsh/parameter's $jobstates is always empty inside $(),
probably because it's a subshell of some sort. `jobs` still works
however, making it rather incongruous. Having access to $jobstates
would be useful for prompts for example, rather than having to parse
the output of `jobs`.

To reproduce:
❯ sleep 1000 &
[1] 210460
❯ jobs
[1]  + running    sleep 1000
❯ echo $jobstates
running:+:210460=running
❯ echo $(jobs)
[1] + running sleep 1000
❯ echo $(echo $jobstates)
(empty)

Follow-Ups:
- Re: [Bug] $jobstates does not work in $()
  - From: Peter Stephenson

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