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Re: completion help?
- X-seq: zsh-users 1143
- From: "Bart Schaefer" <schaefer@xxxxxxxxxxxxxxxx>
- To: Timothy J Luoma <luomat+zsh+users@xxxxxxxxxxxxxxx>, zsh-users@xxxxxxxxxxxxxxx
- Subject: Re: completion help?
- Date: Sun, 16 Nov 1997 18:48:57 -0800
- In-reply-to: <199711170111.UAA01143@xxxxxxxxxxxxxxx>
- References: <199711170111.UAA01143@xxxxxxxxxxxxxxx>
On Nov 16, 8:11pm, Timothy J Luoma wrote:
} Subject: completion help?
} I've never really understood completions functions.
You aren't alone.
} compctl -K allapps 'S[-]' -- run
That assigns the completion `-K allapps' to the three commands S[-], --,
and run. I'm pretty sure that's not what you mean. Normally you'd only
use things that look like 'S[-]' and '--' when the -x option is present.
} I can get the names of the applications using this:
} sed 's/.*\///g' ~/.AppInfo/LaunchBar/Setup|sed 's/\.app$//g'
That's the same as
sed 's/.*\/\(.*\)\.app$/\1/' ~/.AppInfo/LaunchBar/Setup
The \1 in the replacement refers to the stuff inside \( \) in the pattern.
You could write a cryptic-looking variable replacement that's equivalent,
using $(<...), but I wouldn't bother.
} How can I make a function that will allow me to do:
} run [tab]
} run S[tab]
If you can do the former, you can do the latter; zsh takes care of that
part itself, so nothing special is necessary.
reply=( $(sed 's/.*\/\(.*\)\.app$/\1/' ~/.AppInfo/LaunchBar/Setup) )
compctl -K allapps run
compctl -x 'c[-1,-a]' -K allapps -- open
} Clues for the clueless?
The first compctl should be pretty obvious.
The second one says:
-x we're going to use extended completion to
c[,] match a string in some other word relative to the "c"urrent one
-1 and that word is the word immediately preceding the current one
-a and if that word matches "-a"
-K then run the function
-- now we're done defining the completion, so
open is the command to which this completion applies.
Hence `allapps' will generate the completions for `run' and `open -a'.
Bart Schaefer Brass Lantern Enterprises
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