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Re: completion ignoring
- X-seq: zsh-users 1556
- From: Bruce Stephens <b.stephens@xxxxxxxxx>
- To: zsh-users@xxxxxxxxxxxxxxx
- Subject: Re: completion ignoring
- Date: 27 May 1998 17:21:18 +0100
- In-reply-to: Sven Guckes's message of "Wed, 27 May 1998 17:41:41 +0200"
- References: <199805221523.QAA17745@xxxxxxxxxxxxxxxx> <199805221534.LAA13850@xxxxxxxxxxxxxxx> <vb67iyi9c4.fsf@xxxxxxxxxxxxxxx> <980522095232.ZM29476@xxxxxxxxxxxxxxxxxxxxxxx> <19980527142048.A20324@xxxxxxxxxxx> <vbogwj26nw.fsf@xxxxxxxxxxxxxxx> <19980527174141.G1747@xxxxxxxxxxxxxxxxx>
Sven Guckes <guckes@xxxxxxxxxxxxxxxxx> writes:
> Example: Let's assume that the current dir (ie '.') is in the $PATH [*].
> Then the zsh should behave like this:
>
> $ touch foo
> $ chmod 700 foo
> $ f<TAB>
> "foo" is shown
> $ chmod 600 foo
> $ f<TAB>
> "foo" is NOT shown
>
> Is this possible? (I hope that's not in the manual. ;-)
That's what I understood the question to be. And yes, isn't this how
zsh works right now? I don't remember this being changed recently, so
I'd guess it's quite old behaviour?
I just tried with "zsh -f" (3.1.2-zefram3), and it has exactly the
behaviour you list above. Not only that, but "chmod 670 foo" still
has foo not being displayed.
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