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Re: check exit code

X-seq: zsh-users 11656
From: Chris Johnson <cjohnson@xxxxxxxxxx>
To: zsh-users@xxxxxxxxxx
Subject: Re: check exit code
Date: Wed, 18 Jul 2007 08:59:25 -0400
In-reply-to: <589839.11493.qm@xxxxxxxxxxxxxxxxxxxxxxxxx>
Mailing-list: contact zsh-users-help@xxxxxxxxxx; run by ezmlm
References: <20070718095930.GA4936@crematorium> <589839.11493.qm@xxxxxxxxxxxxxxxxxxxxxxxxx>

sac sent me the following 0.7K:

> > I want to check exit code of some command through
> > the $? variable
> > (putting command into 'if' statement is not
> > acceptable).
> > I found currently two ways to do so:
> > if (( $? == 0 )); then; echo true; else; echo false;
> > fi
> > if  ( exit $? ) ; then; echo true; else; echo false;
> > fi
> > 
> > Neither of them seems to be elegant. Maybe there is a builtin which
> > takes number as argument and returns it? Or what would you suggest?
> 
> if [ $? -eq 0 ]; then; echo "ture"; fi

Or try the print builtin:

   print -P '%(?.true.false)'

-- 
Chris Johnson
cjohnson@xxxxxxxxxx
http://www.cs.utk.edu/~cjohnson

References:
- check exit code
  - From: Roman Cheplyaka
- Re: check exit code
  - From: sac

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