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Re: Running "unset path" breaks PATH despite emulation being enabled
- X-seq: zsh-users 22876
- From: Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx>
- To: zsh-users@xxxxxxx
- Subject: Re: Running "unset path" breaks PATH despite emulation being enabled
- Date: Sat, 9 Sep 2017 15:25:12 -0700
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On Sep 9, 2:38pm, Eric Pruitt wrote:
} Subject: Re: Running "unset path" breaks PATH despite emulation being enab
} I would like to replace "zsh" with the absolute path of the Z shell
} interpreter in case the "zsh" being executed is not the first one listed
} in a $PATH folder. After reading through some documentation and
} reviewing the output of "set", I don't see a way to do this. For
} comparison, Bash sets $BASH to the interpreter's path:
I just had a look at the Bash sources. Chet will correct me if I'm wrong,
but as far as I can tell if argv is not already at least a partial
path, then $BASH is set by doing a path search for the first matching
executable. Thus $BASH will be "the first one listed in a $PATH folder"
when argv contains no "/" separators, even if the actual executable
came from somewhere else.
} Is there a similar value in Z shell or a built-in I can use?
$ZSH_ARGZERO in sufficiently recent versions of the shell will give you
the equivalent information, you just have to do the path search part
yourself, which is simple enough with the "=" expander:
[[ =$ZSH_ARGZERO != =$ZSH_NAME ]] && ...
If NO_EQUALS is set then some uses of `whence ...` might be needed.
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