On Nov 27, 2019, at 10:24 AM, Roman Perepelitsa <roman.perepelitsa@xxxxxxxxx> wrote: > >> * if p is present while joining, it must be present while splitting >> * -1s/present/absent/g >> * as the manual says: 0 means ps:\0: > > p simply converts \0 to ascii 0. It's the same as '\0' vs $'\0’. I’m still not clear… > QUOTING > A character may be quoted (that is, made to stand for itself) by preceding it with a `\'. `\' followed by a > newline is ignored. > > A string enclosed between `$'' and `'' is processed the same way as the string arguments of the print builtin, > and the resulting string is considered to be entirely quoted. A literal `'' character can be included in the > string by using the `\'' escape. > > All characters enclosed between a pair of single quotes ('') that is not preceded by a `$' are quoted. Are you saying that ‘\0’ is a quoted null character while $’\0’ is a quoted string with one character which is a null and somehow zsh keeps quoted characters different from quoted strings?
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