On Nov 27, 2019, at 10:24 AM, Roman Perepelitsa <roman.perepelitsa@xxxxxxxxx> wrote:
>
>> * if p is present while joining, it must be present while splitting
>> * -1s/present/absent/g
>> * as the manual says: 0 means ps:\0:
>
> p simply converts \0 to ascii 0. It's the same as '\0' vs $'\0’.
I’m still not clear…
> QUOTING
> A character may be quoted (that is, made to stand for itself) by preceding it with a `\'. `\' followed by a
> newline is ignored.
>
> A string enclosed between `$'' and `'' is processed the same way as the string arguments of the print builtin,
> and the resulting string is considered to be entirely quoted. A literal `'' character can be included in the
> string by using the `\'' escape.
>
> All characters enclosed between a pair of single quotes ('') that is not preceded by a `$' are quoted.
Are you saying that ‘\0’ is a quoted null character while $’\0’
is a quoted string with one character which is a null and somehow
zsh keeps quoted characters different from quoted strings?
Attachment:
smime.p7s
Description: S/MIME cryptographic signature