Re: Java completion for Java files

[Henri Tremblay <henri.tremblay@xxxxxxxxx>]

Yes.

Let's say you have a file in a directory: "src/main/java/org/zsh/Main.java". The class is named Main and is in the package org.zsh in this case.

If you compile it with "javac src/main/java/org/zsh/Main.java" it will generate a file named "src/main/java/org/zsh/Main.class".

So, if you execute it the old way, you would do "java -cp src/main/java org.zsh.Main" which means "Please execute the class with a main() method that is called Main and found in the package org.zsh. The classpath where this class can be found is "src/main".

If you execute it the new way, you don't need to compile with javac. So you only have "src/main/java/org/zsh/Main.java".

And you will execute by doing "java src/main/java/org/zsh/Main.java" and that's it.

Bottom line, indeed, the ".java" at the end tells that it's a java source file and not a compile class found in the classpath that you want to execute.

On Mon, 5 Feb 2024 at 15:44, Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx> wrote:

On Mon, Feb 5, 2024 at 10:04 AM Henri Tremblay <henri.tremblay@xxxxxxxxx> wrote:
>
> Java now supports (since Java 10 I think) command lines like
>
> java Math.java
>
> It will then just compile and launch that java file. But zsh won't autocomplete for that. It only wants a jar, class file or whatever.

The issue is here in the _arguments setup for _java:

    '(-):class:_java_class -m main ${(kv)opt_args[(i)(-classpath|-cp)]}' \
    '*::args:= _normal' \
     && return 0

The (-) says that the first word after "java" must either be an option
(start with "-") or must be a class name.  The completion stops there
unless working on the next word.

How does "java" itself distinguish between a class name and a file
name?  Just whether the string ends in ".java"?