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Re: [ -z $FOO ] seems broken in beta13

X-seq: zsh-workers 1309
From: Zoltan Hidvegi <hzoli@xxxxxxxxxx>
To: A.Main@xxxxxxxxxxxxxxxxx (Zefram)
Subject: Re: [ -z $FOO ] seems broken in beta13
Date: Mon, 10 Jun 1996 19:34:35 +0200 (MET DST)
Cc: olsenc@xxxxxxxxxxxxxxxx, zsh-workers@xxxxxxxxxxxxxxx
In-reply-to: <7884.199606101703@xxxxxxxxxxxxxxxxxxxxxxx> from Zefram at "Jun 10, 96 06:03:37 pm"
Organization: Dept. of Comp. Sci., Eotvos University, Budapest, Hungary
Phone: (36 1)2669833 ext: 2667, home phone: (36 1) 2752368

> >I use [ -z $TERM ] to check for terminal settings, and since we revved up
> >from 2.5, I'm now forced to use $+TERM.
> >
> >Now I get "argument expected".  Is this correct?
> 
> Yes.  If $TERM is empty, then $TERM will be removed from the command
> line completely, leaving `[ -z ]`, which is a syntax error.  If you use
> "$TERM" (note the quotes), then the result will be `[ -z "" ]`, which
> is legal.

Actually POSIX says that

with no arguments test should exit with status 1. 

With 1 argument it should exit true iff that argument is non-null (this
means that `test -n' and `test -z' both exit true).  

With 2 arguments: if $1 is a bang `!' exit true iff $2 is null.  If $1 is
an unary operator, exit true iff the unary test is true.

etc.

I'll modify zsh according to this.

Zoltan

References:
- Re: [ -z $FOO ] seems broken in beta13
  - From: Zefram

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